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Sladkaya [172]
3 years ago
6

What is the range of the relation of centimeters as a function of inches? {5.08, 10.16, 17.78, 25.4, 33.02} all positive integer

s x greater-than-or-equal-to 0 y greater-than-or-equal-to 0
Mathematics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

y>0 Option D

Step-by-step explanation:

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A ladder leaning against a wall makes a 60° angle with the ground. The base of the ladder is 3 m from the building. How high abo
Marysya12 [62]

Answer:

The distance is 5.20m

Step-by-step explanation:

Here, we want to get the height of the ladder

To get this, we need to understand that we have a right triangle, with the base of the triangle as 3 m, the angle at the downward part is 60, and we want to get the height of the triangle

The angle here faces the height we want to calculate

This height is known as the opposite

What we have is the adjacent

Now, the trigonometric identity that relates the opposite and the adjacent is the tan

The tangent of an angle is the ratio of the opposite to the adjacent

Mathematically;

tan 60 = h/3

h = 3 tan 60

h = 5.20 m

The ladder is at a height of 5.20 m above the ground

7 0
3 years ago
Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.
NemiM [27]

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

3 0
3 years ago
an open rectangular cardboard box with a square base is to have a volume of 256cm^3. Find the dimensions of the box if the area
Anit [1.1K]
Let
x------> the length side of the square base of the box
y-------> the height of the box

we know that
volume of the box=b²*h
b=x
h=y
volume=256 cm³
so
256=x²*y------>y=256/x²-------->  equation 1

<span>The amount of material used is directly proportional to the surface area, so we will minimize the amount of material by minimizing the surface area.</span>

surface area of the cardboard=area of the base+perimeter of base*height
area of the base=x²
perimeter of the base=4*x
height=y
surface area=x²+4x*y-----> equation 2
substitute equation 1 in equation 2
SA=x²+4x*[256/x²]-----> SA=x²+1024/x

step 1 
find the first derivative of SA and equate to zero
2x+1024*(-1)/x²=0------> 2x=1024/x²----> x³=512--------> x=8 cm
y=256/x²------> y=256/8²-----> y=4 cm

the answer is
the length side of the square base of the box is 8 cm
the height of the box is 4 cm

5 0
3 years ago
Help! Ill mark you as brain! 15 points!
Alina [70]

Answer:

35 in²

Step-by-step explanation:

The irregular shaped can be divided into two squares and one rectangle, so the area will be the additions of the area of the squares and the rectangle

area of square A = L *B = 3 *3 = 9in²

area of square B = L * B = 4*4 = 16in²

area of rectangle C = L * B = 5 *2 = 10in²

th area of the irregular shape = 9 in² + 16 in² + 10 in² = 35 in²

4 0
3 years ago
A logical argument that is presented in graphical form using boxes and arrows is called a
Ksivusya [100]
When using box and arrows is called using a box plot.
6 0
3 years ago
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