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2 years ago

Set of all numbers greater or equal to -8 but less than 9

Mathematics

1 answer:

Sedaia [141]2 years ago

7 0

Answer:

Could you give more detail?

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Select the correct answer from each drop-down menu. Javier purchased a digital camera for $384. The value of the camera deprecia

Eva8 [605]

Answer:

it will take 3 yrs for the value of camera to reach $162.

Step-by-step explanation:

Pd = P(1-R/100)^T

162 = 384(1-25/100)^T

162/384 = (3/4)^T

27/64 = (3/4)^T

(3/4)^3 = (3/4)^T

T = 3

3 0

2 years ago

Which statement is true

Vsevolod [243]

D is true!!

Hope this helped:)

6 0

3 years ago

By using (17,-13) (17,8) what is the slope

uysha [10]

Y2-y1/x2-x1

8-[-13]/17-17

21/0

this is called undefined because its denominator is zero.

4 0

3 years ago

Find the domain of f(x)=x-9/x squared-81

vagabundo [1.1K]

$f(x)=\dfrac{x-9}{x^2-81}\\\\\text{The domain:}\\\\x^2-81\neq0\qquad\text{add 81 to both sides}\\\\x^2\neq81\to x\neq\pm\sqrt{81}\\\\x\neq-9\ \wedge\ x\neq9\\\\Answer:\ \boxed{\text{All real numbers except -9 and 9}}\to\boxed{x\in\mathbb{R}-\{-9,\ 9\}}$

7 0

3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago