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3 years ago

In the diagram, GH bisects FGI a. X = m b. c. Please help

Mathematics

1 answer:

vladimir1956 [14]3 years ago

5 0

It’s is definitely m. I’m pretty sure

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D is correct. The median is 28, Q1 is 22, Q3 is 38

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3 years ago

10.3.23

Helga [31]

Answer:

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: High school student.

Event B: Is on the swin team.

Probability of selecting a high school student:

Of the 1500 students, 200 are on high school. So

$P(A) = \frac{200}{1500}$

Probability of selecting a high school student who swims:

Of the 1500 students, 45 are high school students who swim. So

$P(A \cap B) = \frac{45}{1500}$

What is the probability that a high school member selected at random is on the swim team?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{45}{1500}}{\frac{200}{1500}} = \frac{45}{200} = \frac{9}{40} = 0.225$

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

4 0

3 years ago

A3-b3=(a-b)(a2+an+b2) 64x6-27

olga nikolaevna [1]

a³-b³=(a-b)(a²+ab+b²)

64x⁶ - 27

64 = 4³,
x⁶ = (x²)³
27 = 3³

64x⁶ - 27 = 4³(x²)³ -3³ = (4x²)³ -3³. Now, we can use a formula where a=4x², b=3

(4x²)³ -3³ = (4x² -3)((4x²)² +4x²*3 + 3²) = (4x² -3)(16x⁴ +12x² + 9)

Answer: 64x⁶ - 27= (4x² -3)(16x⁴ +12x² + 9)

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4 years ago

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Anarel [89]

Answer:

Option A will be your answer

Step-by-step explanation:

hope it helps ..

have a great day!!

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3 years ago

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forsale [732]

Square root of 289 = 17 ft

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3 years ago