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KIM [24]
2 years ago
5

Help me please!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Sav [38]2 years ago
7 0

Answer:

x=-4 and y=4

Step-by-step explanation:

(6x+9y)-(6x+7y)=12-4=8

--> 9y-7y=8

-->2y=8-->y=4

-->6x+7×4=4  -->x=-4

kompoz [17]2 years ago
5 0
Y=4 and X=-4
Next time try to cancel out x first by multiplying by -1 so you can get y first then go from there
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Six is one hundred times ???????????
dezoksy [38]

Answer:

0.06

Step-by-step explanation:

6 is 6.0 and 0.06 times 100 is 6.

5 0
2 years ago
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A grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a
Andru [333]

Answer:

W= 5.744

Step-by-step explanation:

given that a grocery store produce manager is told by a wholesaler that the apples in a large shipment have a mean weight of 6 ounces and a standard deviation of 1.4 ounces

Sample size n= 49

Margin of error = 0.10 (10% risk )

Let us assume X no of apples having mean weight of 6 oz is N(6,1.4)

Then sample mean will be normal with (6, 1.4/7) = (6,0.2)

(Because sample mean follows normal with std error as std dev /sqrt of sample size)

Now required probability <0.10

i.e.P(\bar X

Since x bar is normal we find z score for

P(Z

From std normal distribution table we find that z = 1.28

Corresponding X score =

W= 6-0.2*1.28\\W= 6-0.256 = 5.744

7 0
3 years ago
HELP PLEASE<br> What is the following product?
Naya [18.7K]
The answer would be: 

6 0
3 years ago
Read 2 more answers
Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

5 0
2 years ago
Guys plz help me with a few problems
trasher [3.6K]
It probably gos like this here's my answer for number 1 6/8 and 9/12. for number 3, 10/12 and 15/18.
4 0
2 years ago
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