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Elena L [17]
2 years ago
12

Jake drew this sketch of his triangular rock garden. What is the area of his rock garden?

Mathematics
2 answers:
Oksanka [162]2 years ago
8 0

Answer:

It’s either 30ft or 30ft^2

Charra [1.4K]2 years ago
7 0

Answer:

60

Step-by-step explanation:

To find the area of a triangle you have to multiply base by height base is 12 and height is 5 so you do 12 x 5 = 60! :) hope this helps

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What is the equation of the axis of symmetry for the parabola y=1/2(x-3)^2+5
Rus_ich [418]

The general vertex form equation of the parabola is

y=a(x-h)^2+k

The Axis of Symmetry is given by

x=h

For the given equation the Equation of the Axis of symmetry for the parabola y=1/2(x-3)^2+5 as x=3.

5 0
3 years ago
What is the area of this composite shape?
Varvara68 [4.7K]
<h3>Answer:  51 square inches</h3>

=======================================================

Explanation:

There are a few ways to do this. One way is to divide the figure as shown in the diagram below. I divided it into a rectangle and a triangle. Find the area of the rectangle and triangle, then add up those areas to get the final answer.

A = area of rectangle

A = length*width

A = 7*6

A = 42

B = area of triangle

B = 0.5*base*height

B = 0.5*(6-3)*(13-7)

B = 0.5*3*6

B = 1.5*6

B = 9

C = total area

C = A+B

C = 42+9

C = 51 square inches

6 0
3 years ago
A school has 300 students.If the ratio of boys to girls is 31 to 44, how many more girls are there in the school?
garri49 [273]

Answer:

there would be 52 more girls I think

Step-by-step explanation:

let x = multiplier then

31x =number of boys

44x = number of girls

Boys + girls = 300

44x + 31x =300

75x = 300

x = 300/75

x = 4 is the multiplier

therefore:

44*4 = 176 girls

31*4 = 124 boys

dif = 52 more girls than boys

hope this helped :)

5 0
2 years ago
The figure below shows concentric circles, both centered at 0.0
Rama09 [41]

Answer:

  C.  18 cm

Step-by-step explanation:

The ratio of the sides of the triangle shown is 12 : 15 = 4 : 5. We know it is a right triangle, so we know the missing side length completes the ratio

  3 : 4 : 5 = 9 : 12 : 15

Half of XY is 9 cm, so the length of the entire chord is 18 cm.

_____

The chord is tangent to the inner circle, so makes a 90° angle with the radius to that tangent point. This tells you that the triangle shown is a right triangle. It also tells you that the short radius bisects the chord. The Pythagorean theorem can be used to find the length of the side not shown (half the chord length).

The unknown side (a) can be found from  ...

  15² = 12² +a²

  225 -144 = a² . . . . . . subtract 12²

  81 = a² . . . . . . . . . . .  simplify

  9 = a . . . . . . . . . . . . . take the square root

The chord length is 2a, so is ...

  2(9 cm) = 18 cm . . . . length of chord XY

7 0
3 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
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