1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Valentin [98]
3 years ago
12

Does anybody know this

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0

Step-by-step explanation:

The equation used to determine the amount of radioactive material left is

A = A_0(2)^{-t/HL}

We are have the following given quantities:

t = 30 seconds

A_0 = 50 grams

HL = 6 seconds

Plugging these into our equation we get

A = (50\:\text{grams})(2)^{-(30s/6s)}

\:\:\:\:= (50\:\text{grams})(0.03125)

\:\:\:\:= 1.56\:\text{grams}

You might be interested in
2 (t-4) + 1 math I ready
Roman55 [17]

Answer:

2t-7

Step-by-step explanation:

Not sure what you need ;( hope this helps!

6 0
3 years ago
Read 2 more answers
What is the slope of the line given by the equation y=4x?
umka2103 [35]

Answer:

the slope is 1 over 4, or up 1 right 4.

Step-by-step explanation:

4 0
3 years ago
How to solve the problem
WINSTONCH [101]
As tgose lines are parallel then,

a = 140° ( by alternate interior angles)

then,
tha angle just below "a" on the other paralle line would also be 140° by corresponding angles,

using exterior angle property of triangle

66° + b = 140°

b = 140° -66
= 74°
7 0
3 years ago
A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
3 years ago
What is the volume of a figure with that is 2 inches wide, 7 inches tall and 9 inches<br> Pls help
Mnenie [13.5K]

Answer:

126

Step-by-step explanation:

What is the volume of a figure with that is 2 inches wide, 7 inches tall and 9 inchesn = Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.    

2x7x9 = 126

7 0
3 years ago
Read 2 more answers
Other questions:
  • A square pyramid has a base side of 12 in. and a slant height of 15 in. The lateral area of the pyramid is _____ in.².
    7·1 answer
  • Ignore the mess... I need help with #20 please and thank you
    6·1 answer
  • which unit would you use to measure the volume of a small cardboard box a cubic centimeters b grams c degrees d liters
    12·2 answers
  • Lisa solved 448 math problems for homework over 28 days if she solved the same number of problems each day, how many problems di
    9·1 answer
  • Solve the equation. –3x + 9 = –3(2x + 3) + 3(x – 4) + 1 How many solutions does this equation have? one solution two solutions i
    8·2 answers
  • Which decimal is equivalent to - 13/6
    14·1 answer
  • May i get help with 5-9 questions pls
    8·1 answer
  • With work please and thanks
    10·1 answer
  • Help me pleaseeeeeeeeeeeeeee
    13·1 answer
  • How u solve these I don’t get it :h
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!