Question

Does anybody know this

Answer 1

Step-by-step explanation:

The equation used to determine the amount of radioactive material left is

$A = A_0(2)^{-t/HL}$

We are have the following given quantities:

t = 30 seconds

$A_0$ = 50 grams

HL = 6 seconds

Plugging these into our equation we get

$A = (50\:\text{grams})(2)^{-(30s/6s)}$

$\:\:\:\:= (50\:\text{grams})(0.03125)$

$\:\:\:\:= 1.56\:\text{grams}$