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makkiz [27]
3 years ago
15

Please I really need help with these

Mathematics
1 answer:
MrRissso [65]3 years ago
8 0

Answer:

Idk lol

Step-by-step explanation:

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Determine the equation of the line perpendicular to the line y = –8 through the point (–4, –2).
sesenic [268]
The perpendicular line is x=-4
3 0
3 years ago
Read 2 more answers
M=7,r=8, t=2 ; mr/t = what
galina1969 [7]

Answer:

28

Step-by-step explanation:

Plug in the corresponding numbers to the corresponding variables. Note that:

m = 7

r = 8

t = 2

mr/t = (7 * 8)/2

(7 * (8/2)) = 7 * 4 = 28

28 is your answer.

~

4 0
3 years ago
Line M is represented by the following equation: x − y = 8
PIT_PIT [208]
Let's plug in (18,10) into each answer choice until we find the one that has it as a solution.

A) 2x - y = 26
2(18) - 10 = 26
36 - 10 = 26
26 = 26

Your answer is A.

I'll just do the rest to show that you the they are incorrect.

B) x + y = 18
18 + 10 = 18
28 ≠ 18

C) 2x - 2y = 36
2(18) - 2(10) = 36
36 - 20 = 36
16 ≠ 36

D) x - y = -28
18 - 10 = -28
8 ≠ -28


Your answer is A) 2x - y = 26.
6 0
3 years ago
Read 2 more answers
Could someone please help me with this problem?
natima [27]

Answer:

C

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, 9) and (x₂, y₂ ) = (12, 20)

m = \frac{20-9}{12-4} = \frac{11}{8} → C

7 0
3 years ago
Solve using quadratic formula<br> 6x^2-x=2
Nadya [2.5K]

6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}

7 0
3 years ago
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