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ludmilkaskok [199]
3 years ago
6

Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer

in descending powers of x. (x3 + 6x2 + 3x + 1 ) ÷ (x - 2)
Mathematics
2 answers:
Natalija [7]3 years ago
7 0
X^2+8x+19+39/(x-2)
I cant show how to use synthetic unless I attach a file
Gnesinka [82]3 years ago
3 0

Answer:

[1.(x)²+ 8.(x) + 19] + \frac{39}{(x - 2)}

Step-by-step explanation:

The given polynomial is (x³+ 6x²+ 3x + 1) and we have to divide this polynomial by (x - 2) using synthetic division.

In synthetic division, we divide coefficients of the given terms of the polynomial by (x -2) = 0 ⇒ x = 2

So,      <u>2</u>|      1       6        3         1         ---------[ coefficients]

                   <u>         2       16       38       </u>

                   1       8        19       39

Let me explain it. In first row i have written the coefficients of the terms given in the polynomial 1.x³ + 6.x² + 3x + 1

In the first row I have written 2 in the left side before 1. This is the number by which i am going to divide the coefficients written in the first row.

Now I copied 1 at the bottom (below the line).

Then 2×1 = 2 (written in second row) added with 6 gave 8 at the bottom.

then 8×2 = 16 (written in second row) added with 3 gave 19 at the bottom.

19×2 = 38 (written in second row) added with 1 gave 39 at the bottom.

Now we will rewrite the expression

[1.(x)²+ 8.(x) + 19] + \frac{39}{(x - 2)}

Here highlighted part give in the bracket is the quotient and 19 is the remainder.

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\longrightarrow{\green{- 9 {x}^{2}   +  14x + 16}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\sqrt{49}  + [ \sqrt{81} - x \: (9x   -  14) ] \\ \\   =  \sqrt{7 \times 7}  + [ \sqrt{9 \times 9}   - 9 {x}^{2}   +  14x] \\  \\  =  \sqrt{( {7})^{2} }  + [ \sqrt{ ({9})^{2} }  - 9 {x}^{2}  +  14x ] \\  \\  (∵ \sqrt{ ({x})^{2} } = x ) \\  \\  = 7 + (9 - 9 {x}^{2}   + 14x) \\  \\  = 7 + 9 - 9 {x}^{2}   + 14x \\  \\  =  - 9 {x}^{2}   +  14x + 16

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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