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iris [78.8K]
2 years ago
15

Please help I’m timed!!!

Mathematics
2 answers:
Andrej [43]2 years ago
8 0

Answer:

ZWX and XWZ

Step-by-step explanation:

hope this helps

yKpoI14uk [10]2 years ago
6 0

Answer:

XWZ

ZWX

Step-by-step explanation:

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The enrollment at a community college this year is 115% of last year’s enrollment. If there were 1,240 students enrolled at the
wlad13 [49]

Answer:

Multiply 1240 by 1.15 to get 1426 students enrolled this year.

:

5 0
2 years ago
9(8f+7s) use s=3 and f=2
Margarita [4]
The answer is 333. put the 3 and the 2 in the correct spots. then multiply 8 and 2 which is 16 then 7 and 3 which is 21. then add which is 37. you would have to multiply 37 and 9 and you would get 333.
8 0
3 years ago
It takes 3 hours to wash every window on a building.there are 30 windows. How many minutes does it takes to wask each window
Sveta_85 [38]

Answer:6minutes

Step-by-step explanation:

3 hours =180min

180min divided by 30 windows is 6

8 0
2 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
2 years ago
Read 2 more answers
Find the value of x.<br><br> Please help and can somebody tell me how to find x?
Olegator [25]

Answer:

x = 75°

Step-by-step explanation:

Sum of the interior angles of a triangle = 180°

Therefore,

78° + 27° + x° = 180°

Add like terms

105 + x = 180

105 + x - 105 = 180 - 105 (substraction property of equality)

x = 75°

4 0
2 years ago
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