Solve t/he system of linear equations given by x + y = 1 and ax − by = c, where a, b, c are real numbers. Note: The solution in
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
x + y = 1 → (1)
ax - by = c → (2)
In (1) subtract y from both sides
x = 1 - y → (3)
Substitute x = 1 - y into (2)
a(1 - y) - by = c ← distribute left side
a - ay - by = c ( subtract a from both sides )
- ay - by = c - a ( multiply through by - 1 )
ay + by = a - c ← factor out y from each term on the left side
y(a + b) = a - c ← divide both sides by (a + b)
y = ← substitute into (3)
x = 1 - =
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=
=
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<h2>Given :-</h2>
- 50 men do 10 hours work daily complete work in 20 days
- 80 men do job in 50% time
- Days required
- 1 man may do job in (50 × 20) days =
- 1 man may do job in 1000 days
Now,
- 80 man = 1000/80 = 12.5
Now,
- When hours reduced 50% then we will multiply days by 2
- Total days = 12.5 × 2 = 25 days.
- Option C is correct