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sleet_krkn [62]
3 years ago
7

How does mercury negatively affect human health?

Chemistry
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

The inhalation of mercury vapour can produce harmful effects on the nervous, digestive and immune systems, lungs and kidneys, and may be fata

Explanation:

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When developing an experimental design, which action would improve the
11111nata11111 [884]

Answer:

A

Explanation:

I'm right I took the test

4 0
2 years ago
How many particles are in 697.008 grams of Potassium Sulfate?
g100num [7]

Answer:

174.2592

Explanation:

Trust me.

8 0
3 years ago
How would granite be classified as
vredina [299]

Answer:

Granite is an intrusive igneous rock which means it is cooled slowly deep upper the Earth's crust. It is composed of 25% to 35% quartz and over 50% potassium- and sodium rich feldspars.

Explanation:

4 0
3 years ago
Read 2 more answers
Which formula correctly represents antinomy trichloride?<br> SnS2<br> SnCl3<br> SbCl2<br> SbCl3
max2010maxim [7]

Answer:

SbcI3

Explanation:

The symbol of antimony is 'Sb'.

The symbol of chlorine is 'Cl'

First write down the symbol of the first element.

Use the prefix to determine the atoms of first element. If there is no prefix on element then there is only 1 atom.

Now write down the symbol of the second element.

Use the prefix to determine the atoms of second element.

Use prefix as 'mono' for '1', 'di' for '2', 'tri' for '3' and so on.

3 0
2 years ago
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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
Likurg_2 [28]

Answer: 281 hours

Explanation:-

1 electron carry charge=1.6\times 10^{-19}C

1 mole of electrons contain=6.023\times 10^{23} electrons

Thus  1 mole of electrons carry charge=\frac{1.6\times 10^{-19}}{1}\times 6.023\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

96500\times 2=193000Coloumb of electricity deposits 1 mole or 63.5 g of copper

0.0635 kg of copper is deposited by 193000 Coloumb

11.5 kg of copper is deposited by=\frac{193000}{0.0635}\times 11.5=34952756 Coloumb

Q=I\times t

where Q= quantity of electricity in coloumbs  = 34952756 C

I = current in amperes = 34.5 A

t= time in seconds = ?

34952756 C=34.5A\times t

t=1013123sec=281hours

Thus it will take 281 hours to plate 11.5 kg of copper onto the cathode if the current passed through the cell is held constant at 34.5 A.

8 0
3 years ago
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