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AURORKA [14]
4 years ago
14

What are resources?​

Chemistry
1 answer:
Georgia [21]4 years ago
6 0

Answer:

A resource is a source or supply from which a benefit is produced.

Explanation:

hope it helped :)

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copper hydroxide and potassium sulfate are produced when potassium hydroxide reacts with copper sulfate balanced equation
a_sh-v [17]

This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.

<h3>Balancing chemical equations:</h3>

In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.

For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

2KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

Learn more about balancing chemical equations: brainly.com/question/8062886

8 0
3 years ago
A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
jenyasd209 [6]

Answer:

(B) 0.160 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For K_2CO_3 :

Molarity = 0.200 M

Volume = 20.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.0×10⁻³ L

Thus, moles of K_2CO_3 :

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles of K_2CO_3 = 0.004 moles

For Ba(NO_3)_2 :

Molarity = 0.400 M

Volume = 30.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume =30.0×10⁻³ L

Thus, moles of Ba(NO_3)_2 :

Moles=0.400\times {30.0\times 10^{-3}}\ moles

Moles of Ba(NO_3)_2  = 0.012 moles

According to the given reaction:

K_2CO_3_{(aq)}+Ba(NO_3)_2_{(aq)}\rightarrow BaCO_3_{(s)}+2KNO_3_{(aq)}

1 mole of potassium carbonate react with 1 mole of barium nitrate

0.004 moles potassium carbonate react with 0.004 mole of barium nitrate

Moles of barium nitrate  = 0.004 moles

Available moles of barium nitrate  =  0.012 moles

Limiting reagent is the one which is present in small amount. Thus, potassium carbonate is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of potassium carbonate gives 1 mole of barium carbonate

Also,

0.004 mole of potassium carbonate gives 0.004 mole of barium carbonate

Mole of barium carbonate = 0.004 moles

Also, consumed barium nitrate = 0.004 moles  (barium ions precipitate with carbonate ions)

Left over moles = 0.012 - 0.004 moles = 0.008 moles

Total volume = 20.0 + 30.0 mL = 50.0 mL = 0.05 L

So, Concentration = 0.008/0.05 M = 0.160 M

<u>(B) is correct.</u>

4 0
3 years ago
How many moles are in 4.6 x 10^19 atoms? <br><br> *#27 is the question
velikii [3]
There are 0.000076 moles in 4.6 x 10^19 atoms.
3 0
3 years ago
Help please! -A compound contains 0.013 moles of carbon, 0.039 moles of hydrogen and 0.0065 moles of oxygen. Determine the empir
stepan [7]

A) C2H6O1

To find the emperical formula, divide each mole value by the smallest

For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Emperical formula = C2H6O1

8 0
3 years ago
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Write the following number correct to 2 significant figures: 3644000<br><br> Hurry Plz NO TIME!!!
Nadusha1986 [10]
3644000 rounded to 2 significant figures is equivalent to 3.6
8 0
3 years ago
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