1 step: Place the point of the compass on point M and draw an arc, making sure the width of the compass opening is greater than 1/2MN.
2 step: Place the point of the compass on point N and draw an arc that has the same radius as previous one.
3 step: Connect two points of intersection of drawn arcs. Obtained line will be bisector.
Answer: option D.
<em>Here</em> as the <em>Pentagon</em> is <em>regular</em> so it's <em>all sides</em> will be of <em>equal length</em> . And if we assume It's each side be<em> </em><em><u>s</u></em> , then it's perimeter is going to be <em>(s+s+s+s+s) = </em><em><u>5s</u></em>.And as here , each <em>side</em> is increased by <em>8 inches</em> and then it's perimeter is <em>65 inches</em> , so we got that it's side after increament is<em> (s+8) inches</em> and original length is <em>s inches </em>. And if it's each side is <em>(s+8) inches</em> , so it's perimeter will be <em>5(s+8)</em> and as it's equal to <em>65 inches</em> . So , <em><u>5(s+8) = 65</u></em>


As we assumed the original side to be <em><u>s</u></em> .
<em>Hence, the original side's length 5 inches </em>
Hey there!
3(4y - 12) = 0
3(4y) + 3(-12) = 0
12y - 36 = 0
Add 36 to both sides
12y - 36 + 36 = 0 + 36
Cancel out: -36 + 36 because it give you 0
Keep: 0 + 36 because it help solve for the equation
New equation: 12y = 0 + 36
Simplify it
12y = 36
DIVIDE 12 to both sides
12y/12 = 36/12
Cancel out: 12/12 because that give you 1
Keep: 36/12 because it give you the y-value (also known as your overall result)
New equation: y = 36/12
Simplify it
y = 3
Therefore, your answer should be:
y = 3
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
That cost will be $23.94 in the dollar market
You didn't clarify what the angle is needed for, but still, I'd say never.
If you know two sides of a right triangle you can always find the third using the pythagorean theorem.
Once all sides are known, you can find the three angles: one is surely right, since you have a right triangle. The other two can be found using the sine law.