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9966 [12]
3 years ago
13

Simplify

-%2012%20%7D%20" id="TexFormula1" title=" \frac{x^{2} + 12x + 36 }{x^{2} + 4x - 12 } " alt=" \frac{x^{2} + 12x + 36 }{x^{2} + 4x - 12 } " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

 x + 6

-----------      for all x EXCEPT x = -6

  x + 2

Step-by-step explanation:

Note that the numerator, x^2 + 12 x + 36, factors into (x + 6)^2, and that

the denominator factors into (x + 6)(x - 2).

Thus, the given expression reduces to:

  (x + 6)(x + 6)

-----------------------

  (x + 6)(x + 2)

and can be reduced to:

 x + 6

-----------         This is true for all x EXCEPT x = -6.  At x = -6, the expression

  x + 2            is not defined.

kolbaska11 [484]3 years ago
3 0

Answer:

(x-2)/(2x+8)

Step-by-step explanation:

The first step to solve this expression is to use a² - 2a b + b² = (a - b)² to factor the expression

Factor out 2 from the expression

Write 2x as a difference

Factor out x from the expression

Factor out -2 from the expression

Factor out x + 4 from the expression

Reduce the fraction with x - 2

Finally,, distribute 2 through the parenthesis to find your answer

This means that the correct answer to your question is (x-2)/(2x+8)

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Evaluate the surface integral:S
rjkz [21]
Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle
\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle
\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v

So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
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3 years ago
I need help. Plz! 50 points.
Mrrafil [7]
A. write the question that represents the food supply then write the equation that represents the park attendance
4 0
3 years ago
What is 5-b/2=1 if b=8
Svetach [21]

Answer:

true

Step-by-step explenation:

follow order of operations

5 -8/2 =  5 - (8/2)=  5-4=  1

7 0
3 years ago
Yesterday, stanley's doughnut shop sold 2/3 as many chocolate doughnuts as cinnamon doughnuts. if they sold 7 1/4 trays of cinna
katovenus [111]
You figure out the amount of chocolate doughnuts sold by multiplying 2/3 by 7 1/4

first you change 7 1/4 to an improper fraction:
7 1/4= 29/4
now multiply 2/3×29/4 by multiplying the two numerators then putting that over the two denominators multiplied: (2×29)/(3×4)=58/12
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the answer is Stanley's doughnut shop sold
4 5/6 trays of chocolate doughnuts
5 0
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It is 10 times the value in the number 56,831.
3 0
3 years ago
Read 2 more answers
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