V(t)=t^2+2t+1 integrating we get d(t)
d(t)=t^3/3+t^2+t or more neatly
d(t)=(t^3+3t^2+3t)/3 so
d(2)=(8+12+6)/3
d(2)=26/3
So the particle moves 9 feet (to the nearest foot) in the first two minutes.
The answer is (B) hope that helps
Answ For Lateral Area : When all the side faces are the same: Multiply the perimeter by the "slant length" and divide by 2. This is because the side faces are always triangles and the triangle formula is "base times height divided by 2"er:
Step-by-step explanation: