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allochka39001 [22]
2 years ago
10

Multiply (x + 1)³

Mathematics
2 answers:
Masja [62]2 years ago
6 0

{(x + 1)}^{3}  \\ (x + 1) {(x + 1)}^{2}  \\ (x + 1)( {x}^{2} + 2x + 1) \\  {x}^{3}  + 2 {x}^{2}  + x +  {x}^{2}  + 2x + 1 \\  {x}^{3}  + 3 {x}^{2}  + 3x + 1

Hope it helps

Please give brainliest

nlexa [21]2 years ago
4 0

Answer:

x³+3x²+3x+1

Step-by-step explanation:

=(x+1)(x+1)(x+1)

=(x+1)(x²+x+x+1)

=(x+1)(x²+2x+1)

=(x³+2x²+x+x²+2x+1)

=x³+3x²+3x+1

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2 {x}^{2}  - 3x - 5 ✅

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( {x}^{2}  + 3) - [3x + (8 -  {x}^{2} )] \\  =  {x}^{2}  +3 -  [3x + 8 -  {x}^{2} ] \\  =   {x}^{2}  + 3 - 3x - 8 +  {x}^{2}  \\  = 2 {x}^{2}  - 3x - 5

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}

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What is the domain of the following relation?
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3 years ago
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
UkoKoshka [18]

Answer:

\boxed{m = - \frac{33}{14} }

.

Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

  • m is a slope
  • (x_1,~y_1) and (x_2,~y_2) are the point of the line

.

So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}

.

m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

m = \frac{\frac{11}{2} }{\frac{-7}{3} }

m = \frac{11}{2} \div (-\frac{7}{3} )

m = \frac{11}{2} \times (-\frac{3}{7} )

m = - \frac{33}{14}

.

Happy to help:)

7 0
3 years ago
Read 2 more answers
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