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Mila [183]
3 years ago
6

Area of a parallelogram stripe 12high in 63\4 inbase

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0
12 x 6 3/4
 
= 81

Hope this helps!
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A company's stock begins the week with a price of $43.85 per share. THe price changes by +$2.70 each day for the first two days,
mixas84 [53]

Given:

Initial price of the stock=$43.85

Change for the first two days=+$2.70

Change for next two days=-$1.10

Last day=-$4.45

The objective is to find the price at the last day.

Let's take the price at final day as <em>x</em>.

\begin{gathered} x=43.85+2.70+2.70-1.10-1.10-4.45 \\ x=42.6 \end{gathered}

Hence, the price of the stock at the last day is $42.6

5 0
1 year ago
Solve the inequality.
shusha [124]

Answer:

(3/2)x - 2 < 7

(3/2)x < 9

3x < 18

x < 6

answer is b

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%282%29%20%2B%20g%283%29" id="TexFormula1" title="f(2) + g(3)" alt="f(2) + g(3)" align="absmi
Fofino [41]

Answer:

Step-by-step explanation:

I am sorry but please give detailed question

6 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
Help please and thank you
iren [92.7K]
What do you need what is the question
8 0
3 years ago
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