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djverab [1.8K]
3 years ago
13

Lisa is standing on a dock beside a lake. She drops a rock from her hand into the lake. After the rock hits the surface of the l

ake, the rock's distance from the lake's surface changes at a rate of −2 inches per second. If Lisa holds her hand 5 feet above the lake's surface, how far from Lisa's hand is the rock 4 seconds after it hits the surface?
Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0

Answer:

  • 5 ft 8 in or 68 in

Step-by-step explanation:

<u>In 4 seconds the rock will be at:</u>

  • 2*4 = 8 in from the surface

<u>Add 5 feet to this to get the required distance:</u>

  • 5 ft + 8 in = 5*12 in + 8 in = 68 in
luda_lava [24]3 years ago
3 0

Distance after 8s:-

\\ \rm\longmapsto 4(-2)=-8in

Now

Distance:-

\\ \rm\longmapsto 5-(-8)

\\ \rm\longmapsto 5ft+8in

  • 1ft=12in

\\ \rm\longmapsto 5ft+3/4ft

\\ \rm\longmapsto 23/4ft

\\ \rm\longmapsto 5.7ft

  • Convert to in

\\ \rm\longmapsto 5.7\times 12

\\ \rm\longmapsto 68in

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