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2 years ago

14

In a group of 33 high school students, 10 take French, 11 take Spanish, and 5 take both languages. How many students of group ta

ke neither French nor Spanish?

1 answer:

lilavasa [31]2 years ago

6 0

Answer:

7

Step-by-step explanation:

Add 10,11, and 5

10+11+5=26

subtract 26 from 33

33-26=7

You might be interested in

The difference between an open circle and a closed circle on a graph of an inequality.

Ilia_Sergeevich [38]

A closed circle means that value is included, and an open circle means that value is excluded.

Example:

x > 2 ---- Graphed with an open circle, everything greater than but not including 2

x ≤ 3 ------ Graphed with a closed circle, everything less than and including 3

3 0

2 years ago

The value of 82 is between which two integers?

hoa [83]

Hey there!

Let's look at the squares of all of our answer options. We will compare them to eighty two to see which it belongs in.

A. 36 and 49.

B. 49 and 64.

C. 64 and 81.

D. 81 and 100

As you can see, 82 is in between 81 and 100, so the answer is D. 9 and 10.

Also, the square root of 82 is about 9.05, and this fits our answer.

Have a wonderful day!

8 0

3 years ago

A pole that is 3.1m tall casts a shadow that is 1.29m long. At the same time, a nearby building casts a shadow that is 44.75m lo

Mkey [24]

Let b=height of building. By similar triangles we can say:

b/44.75=3.1/1.29

b=44.75*3.1/1.29

b≈107.54

b≈108 meters (to the nearest whole meter)

8 0

3 years ago

Read 2 more answers

What is the solution to the inequality?<br> −6x+5>−1

Bogdan [553]

Answer:

$\boxed{x$

Step-by-step explanation:

$-6x+5>-1\qquad\text{subtract 5 from both sides}\\\\-6x>-6\qquad\text{change the signs}\\\\6x$

3 0

2 years ago

Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

So

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

2 years ago