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frez [133]
2 years ago
14

In a group of 33 high school students, 10 take French, 11 take Spanish, and 5 take both languages. How many students of group ta

ke neither French nor Spanish?
Mathematics
1 answer:
lilavasa [31]2 years ago
6 0

Answer:

7

Step-by-step explanation:

Add 10,11, and 5

10+11+5=26

subtract 26 from 33

33-26=7

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IAnser this pleaseSnss
Goryan [66]

Answer:

Im pretty sure its x< 3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.
galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: (x-h)^2+(y-k)^2=r^2, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:

NE = \sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}

The radius is √34, which means that r² = 34. So, our equation is:

(x + 6)² + (y + 2)² = 34

Plug in -10 for x and -7 for y:

(x + 6)² + (y + 2)² = 34

x² + 12x + 36 + y² + 4y + 4 = 34

x² + 12x + y² + 4y + 40 = 34

x² + 12x + y² + 4y + 6 = 0

(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7

Since 7 > 0, we know that H lies outside the circle.

6 0
3 years ago
Read 2 more answers
A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen
Leya [2.2K]

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

y = 2 {t}^{2}   + 3t + 500

The growth rate of the first bacteria :

y = 3 {t}^{2}  + t + 300

To find the time that, there will be an equal number of bacteria, we equate the two equation;

3 {t}^{2}  + t + 300 = 2 {t}^{2}   + 3t + 500

3 {t}^{2}  - 2 {t}^{2}   + t  - 3t +  300 - 500 =00

{t}^{2}  - 2t  - 200= 0

We solve for t to get,

t = 15.177

Or

t =  - 13.177

We discard the negative value.

This implies that,

t \approx15

8 0
3 years ago
An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.
Yakvenalex [24]

Answer:

  • <u>3 </u><u>and</u><u> 17</u> are required integers

Step-by-step explanation:

  • Let one integer be x
  • And other integer be y

x = 4y + 5

xy = 51

<u>According to </u><u>question </u><u>:</u>

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

➞ y (4y + 17) - 3(4y + 17) = 0

➞ (y - 3)(4y - 17) = 0

➞ y - 3 = 0

➞ <u>y = 3</u>

Hence,

➞ <u>y = 3</u>

➞ x = 4y + 5

➞ x = 4 (3) + 5

➞ x = 12 + 5

➞<u> </u><u>x = 17</u>

∴ The required integers are <u>3 and 17</u>

7 0
2 years ago
Which expression has a positive value?<br> O (-5)(-9)<br> O 2-4<br> O 12+(-4)<br> O-3+(-7)
PolarNik [594]
(-5)(-9) because a negative times a negative equals a positive.
3 0
3 years ago
Read 2 more answers
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