Answer:
One standard deviation above the mean means a z-score of 1.0. If we put this into the calculator as normalcdf(1,999) = .159
15.9 percent of the athletes would have a distance greater than 20.56 meters.
Now multiply the number of athletes by the percent.
.159 * 40 = 6.346 = about 6 athletes
c. about 6 athletes
Answer:
- Elanor's standardized score is 1.19
- Gerald's standardized score is 0.72
- Elanor has higher score
Step-by-step explanation:
To compare Elanor's and Gerald's math scores, we need to standardize them and calculate their z-scores.
z score can be calculated using the formula
z=
where
- M is the mean score of the exam
- s is the standard deviation of the exam
Elanor's standardized score is:
z(e) =
≈ 1.19
Gerald's standardized score is:
z(g)=
≈ 0.72
Since z(e) > z(g), Elanor has higher score
Y 10x - 13 should be right
Answer:
(-7.5, 3.5)
Step-by-step explanation:




2876.74665 in
After the in you got to put a number 2 above it I don't know how to make the symbol.