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Alex73 [517]
3 years ago
10

When sound waves are reflected back to the source, the reflected sound is called

Physics
2 answers:
sergey [27]3 years ago
6 0
It’s an echo :))))))
Phoenix [80]3 years ago
3 0
Hejehddhshs ajahsvsise akaueegsgw amajsieuege ajwhevegeueje akwjegevsbeieu wish’s
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Where is the centripetal force directed on a banked curve?
Alex777 [14]

Answer:

The net force on a car traveling around a curve is the centripetal force, Fc = m v2 / r, directed toward the center of the curve.

Explanation:LET ME KNOW IF ITS WRONG. HAVE A NICE DAY!!!!!!!!!!

7 0
3 years ago
Read 2 more answers
If the electrons are attracted more by the nucleus because of an additional proton, what would happen to it?
Rus_ich [418]

Answer:

orbital speed of the electrons in their orbit will increase

Explanation:

As we know that centripetal force for electrons will be due to electrostatic attraction force of electron.

So it is given as

F_e = F_c

so we have

\frac{(Ze)(e)}{4\pi \epsilon_0 r^2} = \frac{mv^2}{r}

now on the left side if the force of attraction will increase and hence there must be the change in that part of equation

So here at the same position the speed of the electron

So we can say that correct answer will be

orbital speed of the electrons in their orbit will increase

4 0
3 years ago
When can we be certain that the average velocity of an object is always equal to its instantaneous velocity?
balandron [24]

Answer:

Average velocity is said to be equal to the instantaneous velocity when acceleration is zero. When acceleration of an object is equal to zero, there can be no change in speed or direction.

4 0
3 years ago
IF you are in Space and push a bowling what happens to you and the bowling ball?
Anastaziya [24]

Answer:

The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.

Explanation:

I hope this helps! :D

4 0
3 years ago
Steam enters an adiabatic turbine steadily at 7 MPa, 5008C, and 45 m/s, and leaves at 100 kPa and 75 m/s. If the power output of
marusya05 [52]

Answer:

a) \dot m = 6.878\,\frac{kg}{s}, b) T = 104.3^{\textdegree}C, c) \dot S_{gen} = 11.8\,\frac{kW}{K}

Explanation:

a) The turbine is modelled by means of the First Principle of Thermodynamics. Changes in kinetic and potential energy are negligible.

-\dot W_{out} + \dot m \cdot (h_{in}-h_{out}) = 0

The mass flow rate is:

\dot m = \frac{\dot W_{out}}{h_{in}-h_{out}}

According to property water tables, specific enthalpies and entropies are:

State 1 - Superheated steam

P = 7000\,kPa

T = 500^{\textdegree}C

h = 3411.4\,\frac{kJ}{kg}

s = 6.8000\,\frac{kJ}{kg\cdot K}

State 2s - Liquid-Vapor Mixture

P = 100\,kPa

h = 2467.32\,\frac{kJ}{kg}

s = 6.8000\,\frac{kJ}{kg\cdot K}

x = 0.908

The isentropic efficiency is given by the following expression:

\eta_{s} = \frac{h_{1}-h_{2}}{h_{1}-h_{2s}}

The real specific enthalpy at outlet is:

h_{2} = h_{1} - \eta_{s}\cdot (h_{1}-h_{2s})

h_{2} = 3411.4\,\frac{kJ}{kg} - 0.77\cdot (3411.4\,\frac{kJ}{kg} - 2467.32\,\frac{kJ}{kg} )

h_{2} = 2684.46\,\frac{kJ}{kg}

State 2 - Superheated Vapor

P = 100\,kPa

T = 104.3^{\textdegree}C

h = 2684.46\,\frac{kJ}{kg}

s = 7.3829\,\frac{kJ}{kg\cdot K}

The mass flow rate is:

\dot m = \frac{5000\,kW}{3411.4\,\frac{kJ}{kg} -2684.46\,\frac{kJ}{kg}}

\dot m = 6.878\,\frac{kg}{s}

b) The temperature at the turbine exit is:

T = 104.3^{\textdegree}C

c) The rate of entropy generation is determined by means of the Second Law of Thermodynamics:

\dot m \cdot (s_{in}-s_{out}) + \dot S_{gen} = 0

\dot S_{gen}=\dot m \cdot (s_{out}-s_{in})

\dot S_{gen} = (6.878\,\frac{kg}{s})\cdot (7.3829\,\frac{kJ}{kg\cdot K} - 6.8000\,\frac{kJ}{kg\cdot K} )

\dot S_{gen} = 11.8\,\frac{kW}{K}

4 0
4 years ago
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