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gregori [183]
4 years ago
13

The voltage entering a transformer’s primary winding is 120 volts. The primary winding is wrapped around the iron core 10 times.

The secondary coil is wrapped around the core 4 times. What is the voltage leaving the transformer?
Physics
2 answers:
kolbaska11 [484]4 years ago
8 0

the answer is for the question on edge is 48..................

loris [4]4 years ago
5 0
<u>Answer</u>

 48 Volts  

<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;

Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
            Ns ⇒number of turns in the seconndary coil
            Vp ⇒ primary voltage
             Vs ⇒secondary voltage

Np/Ns = Vp/Vs

10/4 = 120/Vp

Vp = (120 × 4)/10

      = 480/10
      = 48 Volts  

 

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Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the end
yawa3891 [41]

Correct question:

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

a. from the bottom of a hill to the top

b. on a circular nature trail

c. on a sidewalk from his house to the mall

d. from the beginning of a straight track to the end

Answer:

b. on a circular nature trail

Explanation:

As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.

7 0
3 years ago
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You drive a beat-up pickup truck along a straight road for 8.4 km at 70 km/h, at which point the truck runs out of gasoline and
Elan Coil [88]

Answer: a) 10.4km

b) 0.62h

C) 17km/h

d) 9.1km/h

Explanation:

A) suppose you move in the positive direction of an x axis, from a first position of x1 = 0 to a second position of x2 at the station. That second position must be at x2 = 8.4 km + 2.0 km = 10.4 km.

B) time interval Dtwlk (= 0.50 h), but we don't know the driving time interval Dt/dr. However, we know that for the drive the displacement Dx/dr is 8.4 km and the average velocity vavg,dr is 70 km/h.

This average velocity is the ratio of the displacement for the drive to the time interval for the drive:

dv = dx/ dt

dt = dx/dv = 8.4/70 = 0.12h

t = ti + two

t = 0.12 + 0.50 = 0.62h

C) avg speed for the entire trip is the ratio of the displacement of 10.4 km for the entire trip to the time interval of 0.62 h for the entire trip. 

Avg v = distance/time

10.4/0.62 = 16.8km/h

D) average speed is the ratio of the total distance you move to the total time interval you take to make that move. The total distance is 8.4 km + 2.0 km + 2.0 km = 12.4 km. The total time interval is 0.12 h + 0.50 h + 0.75 h = 1.37 h.

Avg speed = 12.4/1.37 = 9.1km/h

6 0
4 years ago
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Vikentia [17]

Answer:

Explanation:

a )

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angular velocity = 2π / T

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ω = 18.84 radian / s

b )

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c )

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d )

This energy comes from the work done by centripetal force which is increased to increase the speed of rotation.

4 0
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mash [69]
Straight lines is my best answer
6 0
3 years ago
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melomori [17]

Answer:

Kinetic energy of an object can't be greater than potential energy.

Explanation:

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4 0
3 years ago
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