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liberstina [14]
3 years ago
7

When can we be certain that the average velocity of an object is always equal to its instantaneous velocity?

Physics
1 answer:
balandron [24]3 years ago
4 0

Answer:

Average velocity is said to be equal to the instantaneous velocity when acceleration is zero. When acceleration of an object is equal to zero, there can be no change in speed or direction.

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(This can be a way to think about it) Nicholas Mikolaj Kopernik,1473–1543 Polish astronomer who declared the now accepted theory that the Earth and the other planets move around the Sun aka the Copernican System.

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3 years ago
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Please help, I don’t get the question.
aalyn [17]

All you have to do is get the culmative effect of the forces by predicting the direction in which each object will move. Just write down what you know and put down questions for your teacher.

6 0
3 years ago
A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat
Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

s = v_0t + gt^2/2

where v_0 is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

3.5 = v_01.1 - 9.81*1.1^2/2

3.5 = 1.1v_0 - 5.94

1.1v_0 = 3.5 + 5.94 = 9.44

v_0 = 9.44 / 1.1 = 8.58 m/s

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s

So they keys would have a downward speed of 2.211 m/s

5 0
3 years ago
A competitive go-cart driver is traveling 32 m/s. He sees a caution flag go up, so he slows at a rate of -1.5 m/s^2 in 10.8 s. W
Svetllana [295]

Answer:

15.8 m/s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 32 m/s.

Acceleration (a) = – 1.5 m/s²

Time (t) = 10.8 s.

Final velocity (v) =?

Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = [final velocity (v) – initial velocity (u)] / time (t)

a = (v – u) /t

With the above formula, we can obtain the final velocity of go-cart driver as follow:

Initial velocity (u) = 32 m/s.

Acceleration (a) = – 1.5 m/s²

Time (t) = 10.8 s.

Final velocity (v) =?

a = (v – u) /t

– 1.5 = (v – 32) / 10.8

Cross multiply

(v – 32) = –1.5 × 10.8

v – 32 = – 16.2

Collect like terms

v = – 16.2 + 32

v = 15.8 m/s

Therefore, the final velocity of go-cart driver is 15.8 m/s.

5 0
3 years ago
One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in
Artemon [7]
I hope this helps you! :)

8 0
3 years ago
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