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3 years ago

What is the slope of the line that passes through the points (-3,12) and (6,24)?

Mathematics

1 answer:

Irina18 [472]3 years ago

7 0

Answer: slope = 4/3

Step-by-step explanation:

(24-12)/(6- -3)

= 12/9

= 4/3

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PLEASE HELP ME RN PLEASE

Advocard [28]

Answer:

$\frac{n^{2} - 1 }{2}$

$\sqrt{29}$

Step-by-step explanation:

Area of triangle=1/2×b×h

$\frac{1}{2} \times (n - 1)(n + 1)$

$\frac{( {n}^{2} + n - n - 1) }{2 }$

$\frac{ {n}^{2} - 1 }{2}$

2. Area of triangle=14

$\frac{ {n}^{2} - 1 }{2} = 14$

${n}^{2} - 1 = 28$

${n}^{2} = 29$

$n = \sqrt{29}$

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3 0

3 years ago

Solve: x/x+2 + 5/x-3 = 25/x2-x-6

Paraphin [41]

Answer:

x1=3 x2=-5

BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution

Step-by-step explanation:

6 0

3 years ago

What vertex does the quadrilateral and the pentagon share?

Leokris [45]

It equals the middle

7 0

4 years ago

O DATA ANALYSIS AND STATISTICS Outcomes and event probability A number cube is rolled three times. An outcome is represented by

Simora [160]

ANSWER

EXPLANATION

For each of the three events, there are 8 possible outcomes, so the probability of each event is,

$P(event)=\frac{favorable\text{ }outcomes}{possible\text{ }outcomes}=\frac{favorable\text{ }outcomes}{8}$

• Event A:, there must be only odd numbers in the last two rolls, which are either ,EOO or OOO,. This event has 2 favorable outcomes, ,so its probability is 1/4,.

• Event B,: this is the complementary event to event A. Here the last two rolls must be even numbers - both or only one of the last two: ,OOE, EEO, EOE, OEE, EEE, OEO,. This event has 6 favorable outcomes, so ,its probability is 3/4,.

• Event C,: this event is when the first and last rolls are even numbers in the same event. This is either ,EOE or EEE,. Since this event has 2 favorable outcomes, ,its probability is 1/4,.

5 0

1 year ago

What is the length of line segment PQ? If you can please explain, thanks.

nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

$\Rightarrow NQ\times NP = MN^2$