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mote1985 [20]
3 years ago
6

Graph the line with the equation y=1/6x-5

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0

Hope it helps you and have a great day

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Identify the constant of proportionality
Sveta_85 [38]

Answer:

When two variables are directly or indirectly proportional to each other, then their relationship can be described as y = kx or y = k/x, where k determines how the two variables are related to one another.

Step-by-step explanation:

This k is known as the constant of proportionality.

3 0
3 years ago
Please help
djyliett [7]

Answer:

x+6<12

Step-by-step explanation:

Since it is going left from 6, we know that x must be less than 6

(if u need me to explain more I can)

8 0
3 years ago
Read 2 more answers
A sample of blood pressure measurements is taken for a group of​adults, and those values​ (mm Hg) are listed below. The values a
scoundrel [369]

Answer:

1. coefficient of variation(systolic) = 13.88%

2. coefficient of variation(diastolic)  = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore  the systolic measurements vary signifcantly less than the diastolic

Step-by-step explanation:

1.  Mean of systolic = ( 117+126+158+96+157+122+116+134+127+122)÷10

      = 127.5

Standard Deviation of systolic = (((117-127.5)^2 +(126-127.5)^2+(158-127.5)^2+ (96-127.5)^2 + (157-127.5)^2 + (122-127.5)^2 + (116-127.5)^2 +(134-127.5)^2 +(127-127.5)^2 +( 122-127.5)^2) ÷ 10)^(0.5)

 SD = 17.7

coefficient of variation(systolic)

= Standard Deviation of systolic /mean of systolic

= \frac{17.7}{127.5} * 100

coefficient of variation(systolic) = 13.88%

2. Mean of diastolic = ( 80+77+76+51+90+89+60+64+72+83) ÷ 10

   = 74.2

Standard Deviation of diastolic  = (((80-74.2)^2 +(77-74.2)^2+(76-74.2)^2+ (51-74.2)^2 + (90-74.2)^2 + (89-74.2)^2 + (60-74.2)^2 +(64-74.2)^2 +(72-74.2)^2 +(83-74.2)^2) ÷ 10)^(0.5)

 SD = 12

coefficient of variation(diastolic)

= Standard Deviation of diastolic /mean of diastolic

 = \frac{12}{74.2} *100

coefficient of variation(diastolic)  = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore  the systolic measurements vary signifcantly less than the diastolic

8 0
3 years ago
A total of 500 voters are randomly selected in a certain precinct and asked whether they plan to vote for the Democratic incumbe
lilavasa [31]

Answer:

The limits are 0.6472 and 0.7528

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 500 surveyed, 350 said they would vote for the Democratic incumbent.

This means that n = 500, \pi = \frac{350}{500} = 0.7

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7 - 2.575\sqrt{\frac{0.7*0.3}{500}} = 0.6472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.7 + 2.575\sqrt{\frac{0.7*0.3}{500}} = 0.7528

The limits are 0.6472 and 0.7528

6 0
3 years ago
Help with exam 11 please
Feliz [49]

Answer:

Step-by-step explanation:

Hope this helps u!!

5 0
3 years ago
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