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zepelin [54]
3 years ago
10

やあ! 退屈だから話したいだけ wanna talk ?

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

sorry............... I posted it in wrong place

Zinaida [17]3 years ago
4 0

yess unnie................

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Given A(2, 3) B(1, 4) C(1, 3) D(-2, 2). How are AB and CD related?
kondaur [170]

The vector AB is not related with the vector CD as k is not the same for each pair of components.

<h3>Are two vectors similar?</h3>

In this question we must prove if the vector AB is a multiple of the vector CD, that is:

\overrightarrow{AB} = k \cdot \overrightarrow {CD}

\vec B - \vec A = k \cdot [\vec D - \vec C]

(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]

(- 1, 1) = k · (- 3, - 1)

Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.

To learn more on vectors: brainly.com/question/13322477

#SPJ1

3 0
2 years ago
Chris Johnson earns $34,850 annually as an engineer. She single on sports your father. The state tax rate in her state is 3% of
Natasha2012 [34]

Answer: 1,045.50

Step-by-step explanation: hope this helps champ.

6 0
4 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
What is the answer to this equation? Must solve for x.<br> x+5=12x−4
natulia [17]

Answer:

x = 9/11

Step-by-step explanation:

x + 5 = 12x - 4

Subtract x from both sides

x + 5 - x = 12x - x - 4

        5   = 11x - 4

Add 4 to both sides

      5+ 4 = 11x - 4 + 4

            9 = 11x

Divide both sides by 11

         9/11 = 11x/11

          9/11 = x

x = 9/11

8 0
3 years ago
Read 2 more answers
Work out the circumference of this circle.
Ksenya-84 [330]
Formula for circumference of circle:
C=2πr
here radius, r=4 cm and π=3.142
Put values in formula.
C=2(3.142)(4)
C=25.1 cm (Rounded to 1 decimal place)

Answer: Circumference of the circle is 25.1 cm (Rounded to 1 decimal place)
6 0
3 years ago
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