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3 years ago

I will GIVE U BRAINLIST AND 20 points help me please

Mathematics

1 answer:

Katena32 [7]3 years ago

5 1

Answer:

$340 Please give me bRIANLIEST NOW:)

Step-by-step explanation:

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Write a polynomial function of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros.

kogti [31]

9514 1404 393

Answer:

f(x) = x³ -5x² +2x +8

Step-by-step explanation:

If the function has a zero of p, then it has a factor of (x-p). The polynomial of least degree will only have factors corresponding to the given zeros:

f(x) = (x -(-1))(x -2)(x -4)

= (x +1)(x -2)(x -4)

= (x² -x -2)(x -4)

f(x) = x³ -5x² +2x +8

6 0

3 years ago

Find r if 0=pi/6 rad sector 64m^2

kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is $\theta=\dfrac{\pi}{6}$ .

To find:

The radius or the value of r.

Solution:

Area of a sector is:

$A=\dfrac{1}{2}r^2\theta$

Where, r is the radius of the circle and $\theta$ is the central angle of the sector in radian.

Putting $A=64,\theta=\dfrac{\pi}{6}$ , we get

$64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}$

$64=\dfrac{\pi}{12}r^2$

$64\times \dfrac{12}{\pi}=r^2$

$\dfrac{768}{\pi}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{768}{\pi}}=r$

$16\sqrt{\dfrac{3}{\pi}}=r$

Therefore, the value of r is $16\sqrt{\dfrac{3}{\pi}}$ m.

6 0

3 years ago

How do you eliminate the parameter theta to find a Cartesian equation of the curve: x=sin(1/2 theta), y=cos(1/2 theta), 0 is les

kiruha [24]

The answer to the problem is as follows:

x = sin(t/2)
y = cos(t/2) 

Square both equations and add to eliminate the parameter t: 

x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 

The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.

6 0

3 years ago

Given: CB bisects

marin [14]

Answer:

Answer to fourth part is :

Angle ABC= Angle DBC

So for fifth part reason answer is ASA congruency.

Step-by-step explanation:

Here we are given that CB bisects angle ABD and angle ACD.

So we have ,

Angle ABC= Angle DBC