Revenue=quantity x price= (-2p+1000) (p)= -2p^2+1000p
The maximum revenue will occur when the first derivative is zero so when 2(-2p)+1000=0;p=250
Which generates 125,000 in revenue
Try prices of 245 and 255 and you will see they both are less than 250 thereby proving the max revenue is 250
c + 9 - 3(c - 10) > 1
We're going to treat this like a regular algebraic equation, thus most algebraic rules and properties apply.
First, apply distributive property.
c + 9 <u>- 3c + 30</u> > 1 (two - signs cancel out, creating a + sign.)
Combine like terms.
<u>-2c + 39</u> > 1
Subtract 39 from both sides.
-2c > <u>-38</u>
Divide both sides by -2.
<u>c < 19</u> (Because we're dividing by a negative number, the sign gets swapped.)
<h3>Your answer is c < 19.</h3>
Answer:
49
..............
Answer: 2
Step-by-step explanation:
The given equation is in slope-intercept form. It is y=mx+b. In this equation, m stands for slope and b stands for y-intercept. Looking back at the equation, we see that in place of m is 2. That tells us that the slope is 2.
Answer:
280.77
Step-by-step explanation:
190.32+90.45 is 280.77. To recheck this answer you can do 280.77 - 90.45 and you get 190.32.