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bulgar [2K]
3 years ago
5

Factorise completely 12xy - 3x^2​

Mathematics
2 answers:
Dafna11 [192]3 years ago
7 0
12xy -3x^2

*Step 1*
Find at the common terms in both
Both have x and 3 common
= 3x(4y - x)
LUCKY_DIMON [66]3 years ago
4 0

Step-by-step explanation:

We need to factorise 3x

2

−12xy

Here we can take 3x common.

Thus we have 3x

2

−12xy=3x(x−4y)

Hence, factors are 3x,(x−4y).

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The circle area is A=\pi r^2 and denote the sector area as A_1. 
Then  \dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}  (the ratio between area is the same as the ratio between coresponding angles).

A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}.

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5. Based on recent results, scores on the SAT test are normally distributed with a mean of 1511 and a standard deviation of 312.
Mekhanik [1.2K]

Answer:

The actual SAT score is 2024.

The equivalent ACT score is 29.49.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

SAT score that is in the 95th percentile

Scores on the SAT test are normally distributed with a mean of 1511 and a standard deviation of 312, which means that \mu = 1511, \sigma = 312

95th percentile is X when Z has a pvalue of 0.95, so X when Z = 1.645. The score is:

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 1511}{312}

X - 1511 = 1.645*312

X = 2024

The actual SAT score is 2024.

Equivalent ACT score:

The equivalent ACT score is the 95th percentile of ACT scores.

Scores on the ACT test are normally distributed with a mean of 21.1 and a standard deviation of 5.1, which means that \mu = 21.1, \sigma = 5.1. So

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 21.1}{5.1}

X - 21.1 = 1.645*5.1

X = 29.49

The equivalent ACT score is 29.49.

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