Answer:
For t=3 sec the velocity change from positive to negative
Step-by-step explanation:
we have
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This is the equation of a vertical parabola open downward (the leading coefficient is negative)
where
s(t) is the distance in feet
t is the time in seconds
We know that
To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation
The turning point of the quadratic equation is the vertex
so
Convert the quadratic equation into vertex form
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Factor -16
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Complete the square
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
Rewrite as perfect squares
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The vertex is the point (3,244)
therefore
For t=3 sec the velocity change from positive to negative
Ok so for number 5, AB is proportional to BC just like PQ is proportional to QR. AB = 9, BC = 15, PQ = 3, and QR = x. 9/15 = 3/x. Cross Multiply: This gives you - 9x = 45. Divide both sides by 9, and you get x = 5. QR = 5
6/56 = 3/28........................
The length of a rectangle is 12 inches more than its width. What is the width of the rectangle if the perimeter is 42 inches?
x best represents .
x + 12 best represents
I hope this helps
<span>372° - 360° = 12°</span>