A shipping service restricts the dimensions of the boxes it will ship for a certain type of service.
1 answer:
Answer:
Then the answer is option a
a. 0<x 10
Step-by-step explanation:
perimeter + height is less than 130 inches.
If height is 60 inches.then perimeter left is 70 inches.
If perimeter was more than 70 inches then perimeter 60 more than the height would be more than 130.
perimeter of rectangle is
It has two widths and two lengths because that's what rectangles do.
width of base "x"
Then the length is 2.5x
perimeter = 2 width + 2 length
=
= 2x + 5x
= 7x
but perimeter can't be more than 70 inches.
So x can't be more than 10 inches because if x was more than 10 inches, then 7x which is perimeter would be more than 70 inches.
7x + 60 ≤ 130
7x ≤ 70
x ≤ 10
Then the answer is option a
a. 0<x≤10
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Answer:
See explanation
Step-by-step explanation:
Solution:-
- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:
P ( x ) = 50 Ln ( 50 / x ).
- The point price elasticity ( E ) of demand is given by:
- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.
- To determine the " dP / dx " by taking the first derivative of the given relation:
P ( x ) = 50 Ln ( 50 / x ).
d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]
= - 50 / x
- Hence the point price elasticity of demand is given by:
E = - ( P / x ) * ( 50 / x )
E = -50*P / x^2
- For an inelastic demand, ! E ! is < 1:
! -50*P / x^2 ! < 1
50*P / x^2 < 1
P < x^2 / 50
- For an unitary demand, ! E ! is = 1:
! -50*P / x^2 ! = 1
50*P / x^2 = 1
P = x^2 / 50
- For an inelastic demand, ! E ! is > 1:
! -50*P / x^2 ! > 1
50*P / x^2 > 1
P > x^2 / 50
2)
If the unit price is increased slightly from $50, will the revenue increase or decrease?
- We see from the calculated demand sensitivity d P / dt:
d P ( x ) / dx = - 50 / x
- We see that as P increases the from P = $50, the quantity of goods demanded would be:
50 = 50 ln(50/x)
1 = Ln ( 50 / x )
50/x = e
x = 50 / e
Then,
d P ( x ) / dx = - 50 / ( 50 / e )
d P ( x ) / dx = - e
- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.
- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:
Revenue R ( x ) = P ( x ) * x
= 50*x*ln(50/x)
Then the product of price and quantity goods also decreases; hence, revenue decreases.
Step-by-step explanation:
answer is in photo above
