A shipping service restricts the dimensions of the boxes it will ship for a certain type of service.
1 answer:
Answer:
Then the answer is option a
a. 0<x 10
Step-by-step explanation:
perimeter + height is less than 130 inches.
If height is 60 inches.then perimeter left is 70 inches.
If perimeter was more than 70 inches then perimeter 60 more than the height would be more than 130.
perimeter of rectangle is
It has two widths and two lengths because that's what rectangles do.
width of base "x"
Then the length is 2.5x
perimeter = 2 width + 2 length
=
= 2x + 5x
= 7x
but perimeter can't be more than 70 inches.
So x can't be more than 10 inches because if x was more than 10 inches, then 7x which is perimeter would be more than 70 inches.
7x + 60 ≤ 130
7x ≤ 70
x ≤ 10
Then the answer is option a
a. 0<x≤10
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Answer:
All of them? Pls reply if so!
Step-by-step explanation:
To convert a fraction to a decimal just the divide the bottom into the top.
To convert a decimal into a fraction just put the decimal over 1 or divide the decimal by preference of tenths, hundredths, or thousandth place.
Answer:
72 feet from the shorter pole
Step-by-step explanation:
The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.
The shorter pole height as a fraction of the total pole height is ...
18/(18+24) = 3/7
so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:
d/168 = 3/7
d = 168·(3/7) = 72
The wire should be anchored 72 feet from the 18 ft pole.
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<em>Comment on the problem</em>
This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.
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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:
L = √(18²+x²) + √(24² +(168-x)²)
and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.
