Question

One number is 11 less than the other number if their sum is increased by 8 the results is 71

Answer 1

x = number 1

x - 11 = number 2

(x + x-11) + 8 = 71

Simplify the left side.

2x - 3 = 71

Add 3 to both sides

2x = 74

Divide both sides by 2

x = 37

x - 11 = (37) - 11 = 26