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2 years ago

You withdraw $40 each month from your savings account. what integer represents the change in your balance after 4 months?

Mathematics

1 answer:

kotegsom [21]2 years ago

5 0

Answer:

The balance would be $160 from whatever it was before the 4 months.

Step-by-step explanation:

Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.

So if the balance before was $40, then the new balance after 4 months would be $200.

If there's no money previously, then there is now $160 after 4 months.

If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.

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olganol [36]

It's a kite or a rhombus.

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2 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

X-25/14=6/7 find the solution

Lubov Fominskaja [6]

$x= \frac{6}{7} + \frac{25}{14} = \frac{12+25}{14} = \frac{37}{14}$

4 0

3 years ago

Hey um... I have a question about Cumulative frequency diagram. Its in the picture. Please help I will give you reward I promise

Mice21 [21]

Answer: see below

Step-by-step explanation:

(i)

200/2 = 100

Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.

(ii)

First, find the lower quartile —> 200/4 = 50

Upper quartile —> 200/(3/4) = 150

Find the difference: 150 - 50 = 100

So the interquartile range is 100

For detailed, step-by-step explanations you can visit my fiverr account: kesja_

I provide detailed explanations for math questions for as little as $1!

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2 years ago

Given m parallel to n, find the value of x, (7x+14) and (9x-8)

iVinArrow [24]

Answer:

x=11

Step-by-step explanation:

(7x+14)=(9x-8)

7x-9x=-14-8

-2x=-22

-2x/-2=-22/-2

x=11

8 0

2 years ago