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Scorpion4ik [409]
3 years ago
11

Rita needed to solve t problem for homework. Below is the problem and her work. Is she correct? Why or Why

Mathematics
1 answer:
Lemur [1.5K]3 years ago
8 0
There’s no image added :(
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When he was born Frank weighed 4.2 kg.This was 500g more than Sally.What did Sally weigh at birth?​
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3.7kg

Step-by-step explanation:

4.2kg =4200

4200-500=3700

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The beads in 7 bracelets if 4 bracelets have 96 bead
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96/4=24 beads in 1 bracelet
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5 0
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Part A: The Sun produces 3.9 ⋅ 1033 ergs of radiant energy per second. How many ergs of radiant energy does the Sun produce in 1
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I have the answer to part A. just do 10,000,000* 1.55 and you should get 15,000,000.

Step-by-step explanation:

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3 years ago
Help 80 points A concrete planter is formed from a square-based pyramid that was inverted and placed
Rufina [12.5K]

Answer:

<h3>(A)</h3>

The slant height of the pyramid refers to the height of a face of the pyramid.

Notice that each slant height forms a right triangle like the image attached shows, where the hypothenuse is the slant height. Additionally, the bottom leg is 1 yard, because is half of the base side, and the other leg is 2 yard. Using Pythagorean's Theorem, we have

h^{2} =1^{2} +2^{2} \\h=\sqrt{1+4}=\sqrt{5}

Therefore, the slant height is the square root of 5 yard.

<h3>(B)</h3>

The surface area of the composite figure is the sum of the surface area of both volumes.

<h3>Surface area of the cube.</h3>

S_{cube}=5(2yd)^{2}  =20 yd^{2}

Notice that we only included 5 faces of the cube, that is because the sixth is the base of the pyramid, so if we include it here, we would have the wrong total surface area.

<h3>Surface area of the pyramid.</h3>

S_{pyramid}=\frac{1}{2}pl

Where p is the perimeter of the base and l is the slant height.

S_{pyramid}=\frac{1}{2}(8yd)(\sqrt{5}yd )=4\sqrt{5}yd ^{2}

Therefore, the surface od the composite figure is

S_{total}=20yd^{2} +4\sqrt{5} yd^{2} \approx 29.94 yd^{2}

<h3>(C)</h3>

To find the cubic yards of concrete, we need to subtract the volume of the figures, because the concrete would be inside the space between the cube and the pyramid.

V_{concrete}=V_{cube}  -V_{pyramid}=l^{3}-  \frac{1}{3}l^{2}h

Where l=2yd and h=2yd

V_{concrete}=2^{3}-\frac{1}{3}(2)^{2} (2)=8-\frac{8}{3} \approx  5.33 yd^{3}

Therefore, it would be needed 5.33 cubic yards of concrete to make the planter.

8 0
3 years ago
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