Simplify. 52 • (4 + 23)
1 answer:
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Answer:
The inspector's claim has strong statistical evidence.
Step-by-step explanation:
To answer this we have to perform a hypothesis test.
The inspector claimed that the actual proportion of code violations is greater than 0.07, so the null and alternative hypothesis are:
We assume a significance level of 0.05.
The sample size is 200 and the proportion of the sample is:
The standard deviation is
The z-value can be calculated as
The P-value for this z-value is P=0.00914.
This P-value is smaller than the significance level, so the effect is significant and the null hypothesis is rejected.
The inspector's claim has strong statistical evidence.