Question

A wheelbarrow of mass 20 kg accelerates from rest and reaches speed of 10m/S2 in 5 seconds.its force?​

Answer 1

Answer:

$\boxed {\boxed {\sf 40 \ Newtons}}$

Explanation:

We are asked to find the force of a wheelbarrow. According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= \ m \times a$

1. Calculate Acceleration

The mass of the wheelbarrow is 20 kilograms. We are not given the acceleration, so we must calculate it using the following formula.

$a= \frac{v_f-v_i}{t}$

The wheelbarrow starts at rest or 0 meters per second (initial velocity) and accelerates to reach 10 meters per second (final velocity) in 5 seconds (time).

• $v_f=$10 m/s
• $v_i=$0 m/s
• t= 5 s

Substitute these values into the formula.

$a= \frac{ 10 \ m/s-0 \ m/s}{5 \ s}$

Solve the numerator.

$a= \frac{10 \ m/s}{5 \ s}$

Divide.

$a= 2 \ m/s/s$

$a= 2 \ m/s^2$

2. Calculate Force

Now we know the mass and acceleration of the wheelbarrow

• m= 20 kg
• a= 2 m/s²

Substitute the values into the force formula.

$F= 20 \ kg \times 2 \ m/s^2$

$F= 40 \ kg*m/s^2$

Convert the units. 1 kilogram meter per square second is equal to 1 Newton, so our answer of 40 kilogram meters per square second is equal to 40 Newtons.

$F= 40 \ N$

Answer 2

Answer:

40 N

Explanation:

We know that

F = ma

and

a = (v - u)/t

So,

F = m(v - u)/t

F = 20(10 - 0)/5

F = 20(10/5)

F = 20(2)

F = 40 N