Combine like terms: x^3+x^3 = 2x^3
2x^2
-x
-10
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(f+g)(x) = 2x^3 + 2x^2 - x - 10 (answer)
Answer:
a
Step-by-step explanation:
Line BC needs to be congruent to EF
Answer:
$13500
Step-by-step explanation:
Given
Each tile cover one ninth of a square yard and each tile costs $3
First, area of the Swimming Pool(from the diagram)
=Area of Left rectangle(length=20,breadth=10)+ Area of Square in middle(side=10)+Area of right rectangle(length=20,breadth=10)
![(\text{area of rectangle}= length\times breadth \\\text{ area of square}= side \times side)](https://tex.z-dn.net/?f=%28%5Ctext%7Barea%20of%20rectangle%7D%3D%20length%5Ctimes%20breadth%20%5C%5C%5Ctext%7B%20area%20of%20square%7D%3D%20side%20%5Ctimes%20side%29)
![= 20\times 10+ 10\times 10+ 20 \times 10\\= 200+100+200\\=500yards](https://tex.z-dn.net/?f=%3D%2020%5Ctimes%2010%2B%2010%5Ctimes%2010%2B%2020%20%5Ctimes%2010%5C%5C%3D%20200%2B100%2B200%5C%5C%3D500yards)
We have to calculate how many tiles make up 500 yards
As given each tile is one ninth of a yard
⇒Number of tiles that make up 500 yards, n
![=\frac{500}{\frac{1}{9} } =\frac{500\times9}{1} =4500](https://tex.z-dn.net/?f=%3D%5Cfrac%7B500%7D%7B%5Cfrac%7B1%7D%7B9%7D%20%7D%20%3D%5Cfrac%7B500%5Ctimes9%7D%7B1%7D%20%3D4500)
⇒ As each tile costs $3
Therefore total cost to tile the floor
![= \text{total number of tiles}\times 3\\=n\times 3\\=4500 \times 3\\=13500](https://tex.z-dn.net/?f=%3D%20%5Ctext%7Btotal%20number%20of%20tiles%7D%5Ctimes%203%5C%5C%3Dn%5Ctimes%203%5C%5C%3D4500%20%5Ctimes%203%5C%5C%3D13500)
Therefore total cost of tiles=$13500