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FromTheMoon [43]
3 years ago
5

If a = b + 6 but a also = b * 3, what are the variables?

Mathematics
2 answers:
Ratling [72]3 years ago
4 0
The b would equal 3 because 3 + 6 = 9 and 3 * 3 = 9
netineya [11]3 years ago
4 0

Answer:

  • a = 9, b = 3

Step-by-step explanation:

<u>Given:</u>

  • a = b + 6
  • a = b*3

<u>Then, eliminate a:</u>

  • b + 6 = 3b
  • 2b = 6
  • b = 3

<u>Find a:</u>

  • a = 3+ 6 = 9
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Find the equation of the line
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Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6x - 2 ← is in slope- intercept form

with slope m = 6

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{6}, thus

y = - \frac{1}{6} x + c ← is the partial equation

To find c substitute (6, - 2 ) into the partial equation

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = - \frac{1}{6} x - 1 ← equation of line

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4 years ago
The distance an object falls when dropped from a tower varies directly as the square of the time it falls. If the object falls 1
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288 feet because your doubling the time so you double the feet 
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If p=3q^3 , is p a function of q ?
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3 years ago
Find a positive number for which the sum of it and its reciprocal is the smallest​ (least) possible. Let x be the number and let
Allisa [31]

Answer:

S(x) = x + \frac{1}{x} --- Objective function

Interval = \{x:x=1\}

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

x + \frac{1}{x}

Hence, the objective function is:

S(x) = x + \frac{1}{x}

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

S'(x) = 1 - \frac{1}{x^2}

Equate S'(x) to 0 in order to solve for x

0 = 1 - \frac{1}{x^2}

Subtract 1 from both sides

0 -1 = 1 -1 - \frac{1}{x^2}

-1 = - \frac{1}{x^2}

Multiply both sides by -1

1 = \frac{1}{x^2}

Cross Multiply

x^2 * 1 = 1

x^2  = 1

Take positive square root of both sides because x is positive

\sqrt{x^2} = \sqrt{1

x = 1

Representing x using interval notation, we have

Interval = \{x:x=1\}

To get the smallest sum, we substitute 1 for x in S(x) = x + \frac{1}{x}

S(1) = 1 + \frac{1}{1}

S(1) = 1 + 1

S(1) = 2

<em>Hence, the smallest sum is 2</em>

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3 years ago
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Answer:

24 - 24 = 0 (carols age past tense)

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carol is now 72 yr

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