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IceJOKER [234]
3 years ago
14

Guys please help i need to pass this!!

Chemistry
1 answer:
astraxan [27]3 years ago
7 0

Answer:

Towards the center of the earth.

Explanation:

That is the gravitational pull for us on earth like we are pulled to the center of earth not the atmosphere high up in the sky hope this helps? I know you can pass this! You got it the fact that you got that far is proof.

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Can someone please help?
erma4kov [3.2K]

Answer:

On Question 3

Explanation:

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4 0
3 years ago
Read 2 more answers
What is the volume of<br> NH4 NO3(s) — N2O(g) + 2H2O(g)
tatiyna

Answer:

Explanation:

NH4NO3(s) N2O(g) + 2H2O(g) What is the total volume of gases produced at 546 K and 1.00 atm pressure when 240 g of ammonium nitrate undergoes the above decomposition reaction? A) 9 × 22.4 L B) 3 × 22.4 L C) 12 × 22.4 L D) 18 × 22.4 L E) 6 × 22.4 L

8 0
2 years ago
A weak acid. What is the pH of a 0.1 M solution of acetic acid (pKa = 4.75)?
Rashid [163]

Answer:

pH of acetic acid solution is 2.88

Explanation:

pK_{a}=4.75

or, -log(K_{a})=4.75

or, K_{a}=10^{-4.75}=1.78\times 10^{-5}

We have to construct an ICE table to determine concentration of H^{+} and corresponding pH. Initial concentration of acetic acid is 0.1 M.

CH_{3}COOH\rightleftharpoons CH_{3}COO^{-}+H^{+}

I(M):  0.1                            0                    0

C(M): -x                              +x                 +x

E(M): 0.1-x                         x                    x

So, \frac{[CH_{3}COO^{-}][H^{+}]}{[CH_{3}COOH]}=K_{a}

or, \frac{x^{2}}{0.1-x}=1.78\times 10^{-5}

or, x^{2}+(1.78\times 10^{-5}\times x)-(1.78\times 10^{-6})=0

So, x=\frac{-(1.78\times 10^{-5})+\sqrt{(1.78\times 10^{-5})^{2}+(4\times 1\times 1.78\times 10^{-6})}}{2\times 1}(M)

so, x=1.33\times 10^{-3}M

Hence pH=-log[H^{+}]=-log(1.33\times 10^{-3})=2.88

3 0
3 years ago
A 5.5 g sample of a substance contains only carbon and oxygen. Carbon makes up 35% of the mass of the substance. The rest is mad
Mamont248 [21]

Answer:

The correct answer is option (1).

Explanation:

Mass of the sample = 5.5 g

Percentage of carbon in sample = 35 %

Percentage of oxygen in sample = 100% - 35%

\%=\frac{\text{Mass of the element in the sample}}{\text{Mass of sample}}\times 100

Mass of carbon in a sample: (35%) of 5.5 g

\frac{35}{100}\times 5.5 g=1.925 g

Mass of oxygen in a sample: (100%-35%) of 5.5 g

\frac{100-35}{100}\times 5.5 g=3.575 g

6 0
3 years ago
Make a t chart comparing physical and chemical changes
madam [21]
FOLLOWING!!!!!!!!!!!!!!!!!!
8 0
3 years ago
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