Answer: C3H4 (Propayne) have a triple bond.
Explanation:
The hydrocarbons which having triple bond are called alkyne. The general formula of alkyne is CnH2n-2. Here, n is number of carbon atoms.
In alkyne, the number of hydrogen atom is 2 less than double the number of carbon atoms.
Thus, the compound C3H4 (Propyne) have a triple bond.
Answer is: n (number of fluorine atoms) is 6, formula of the compound is XeF₆.
m(F) = 0.8682 g; mass of fluorine.
n(F) = m(F) ÷ M(F).
n(F) = 0.8682 g ÷ 19 g/mol.
n(F) = 0.0457 mol; amount of substance.
m(Xe) = 1.00 g.
n(Xe) = 1.00 g ÷ 131.293 g/mol.
n(Xe) = 0.00761 mol.
n(Xe) : n(F) = 0.00761 mol : 0.0457 mol.
n(Xe) : n(F) = 1 mol : 6 mol.
Answer:
for me to be able to get to the office today and I will be in the office tomorrow and will be able the get time final
<h2>d=density, m=mass, v=volume</h2>
1. 17.2kg=17200g
so knowing that d=m/V, use V=m/d to calculate the volume
v=17200/5.75
and then devide by 1000 to convert cm3 to dm3 and the answer will be in dm3
2. d=m/v
v=0.5l
m=425g
so use the formula and you will get d=425/0.5=850g/l
3. use d=m/v again, but not before rewriting the formula for volume: m=vd and convert dm3 to cm3
1dm3=1000cm3
so 0.987dm3 =987 cm3
now m=987cm3 * 10.5g/cm3 and the answer will be in grams
