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3 years ago

Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Chemistry

1 answer:

otez555 [7]3 years ago

8 0

Answer:

<h3>option D</h3>

Explanation:

<h3>Is wire A connected to the light bulb </h3>

<h3>because it is series connection</h3>

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FREE 60 points & maybe one brain liest!!!!!!

Rudiy27

Answer:

THANKS SO MUCH

I actually did the same thin last week

Explanation:

4 0

3 years ago

Read 2 more answers

Answer each of the following questions with increases, decreases, or does not change.

Kaylis [27]

Answer:

1) Increases

2) decreases

3) increases

4) decreases

Explanation:

When the intermolecular forces in a liquid increases, the greater vapour pressure of the liquid decreases accordingly.

Since the vapour pressure is proportional to temperature, as temperature increases, the vapour pressure increases alongside.

As intermolecular forces increases, the boiling point increases accordingly since more energy is required to break intermolecular bonds.

Lastly, the greater the surface area, tell greater the vapour pressure since more liquid surface area is now available.

7 0

4 years ago

Let us assume that fe(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented

Yuki888 [10]

17.8 mL NaOH

<em>Step 1.</em> Write the chemical equation

Fe^(2+) + 2NaOH → Fe(OH)2 + 2Na^(+)

<em>Step 2.</em> Calculate the moles of Fe^(2+)

Moles of Fe^(2+) = 500 mL Fe^(2+) × [0.0230 mmol Fe^(2+)]/[1 mL Fe^(2+)]

= 11.50 mmol Fe^(2+)

<em>Step 3.</em> Calculate the moles of NaOH

Moles of NaOH = 11.50 mmol Fe^(2+) × [2 mmol NaOH]/[1 mmol Fe^(2+)]

= 23.00 mmol NaOH

<em>Step 4.</em> Calculate the volume of NaOH

Volume of NaOH = 23.00 mmol NaOH × (1 mL NaOH/1.29 mmol NaOH)

= 17.8 mL NaOH

3 0

4 years ago

A sample of gas in a closed container at a

Paladinen [302]

Answer:

8.07 atm

Explanation:

Use Gay-Lussac's law and rearrange forumula

Change C to K

- Hope that helps! Please let me know if you need further explanation.

5 0

3 years ago

Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso

Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

$\Delta T_{f}= k_{f}m$

where, $\Delta T_{f}$ = depression in freezing point

$k_{f}$ = molal depression constant (20.0 $^{o}Ckg/mole$ )

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles = $\frac{given mass in g}{molar mass}$

given mass of biphenyl solute = 0.925 g

Molar mass of biphenyl = 154.21 g/mol

Put the values,

number of moles of biphenyl = $\frac{0.925 g}{154.21 g/mol}$

= $0.0059 mole$

Molality = $\frac{number of moles of biphenyl solute}{mass of the solvent in kg}$

Mass of cyclohexane solvent = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane = $\frac{25.0}{1000}$

= 0.025 kg

Now, put the values in the formula of molality:

Molality = $\frac{0.0059 mole}{0.025 kg}$

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

$\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg$

= $4.72 ^{o}C$

Now, $\Delta T_{f} = T_{solvent} - T_{solution}$

$4.72 ^{o}C = 6.50^{o}C - T_{solution}$

$T_{solution} = 6.50^{o}C- 4.72 ^{o}C$

= $1.78^{o}C$

Hence, freezing point of the solution is $1.78^{o}C$ .

4 0

3 years ago

Read 2 more answers