find the answer in the attached image. please mark as brainliest if it is helpful.
Answer:
0.0983 M
Explanation:
First, we need to find the formulas of the reactants. Potassium forms the ion K⁺, and iodide is the ion I⁻, thus potassium iodide is KI. Silver forms the ion Ag⁺, and nitrate is the ion NO₃⁻, thus silver nitrate is AgNO₃. In the reaction, the cations will be replaced:
KI(aq) + AgNO₃(aq) → KNO₃(aq) + AgI(s)
AgI is an insoluble salt, so it will precipitate, and all nitrates are soluble, thus KNO₃ will be in the ionic form: K⁺ and NO₃⁻. 1 mol of KNO₃ = 1 mol of K⁺.
The molar mass of KI is 166 g/mol, thus the number of moles that is added is:
nKI = mass/molar mass
nKI = 5.71/166 = 0.0344 mol
And the number of moles of AgNO₃ is given as 64mM = 0.064 mol. Because the stoichiometry is 1:1, AgNO₃ is in excess, thus, all the KI will react and form 0.0344 mol of KNO₃. So, nK⁺ = 0.0344 mol. The molarity is the number of moles divided by the volume (350 mL = 0.350 L):
0.0344/0.350 = 0.0983 M
Answer:
The answer to your question is 2 molecules
Explanation:
Unbalanced chemical reaction
H₂(g) + N₂(g) ⇒ NH₃ (g)
Reactants Elements Products
2 H 3
2 N 1
Balanced chemical reaction
3H₂(g) + N₂(g) ⇒ 2NH₃ (g)
Reactants Elements Products
6 H 6
2 N 2
From the balanced chemical reaction we conclude that when 3 molecules of hydrogen react with one molecule of nitrogen, 2 molecules of ammonia will be formed.
Monitoring and regulating nuclear waste generated and issues associated to it the US.
Answer:
See Explanation
Explanation:
In the first case, when potassium iodide is added to an aqueous bromine solution, a chemical reaction occurs as follows;
Br2(l) + 2 KI(aq) = 2 KBr(aq) + I2(l)
This reaction produces iodine solution which is brown in colour.
Secondly, when potassium iodide is added to aqueous chlorine solution, the following reaction occurs;
2KI(aq) + Cl2(l)→ 2KCl(aq) + I2 (l)
This reaction also yields iodine solution which is brown in colour.
KI(aq) + I2(l) -------->K^+(aq) + I3^-(aq)
The I3^-(aq) solution appears brown at high concentrations.
