The relevant equation we can use in this case would be:
v^2 = v0^2 + 2 a d
where:
v is our final velocity or landing velocity = ?
v0 is the initial velocity = 5 m/s
a is acceleration due to gravity = 9.81 m/s^2
d is distance = 25 m
So:
v^2 = 5^2 + 2 (9.81) 25
v^2 = 515.5
<span>v = 22.70 m/s</span>
Answer:
Block A has the greatest density.
Explaination:
Block A density:0.0625 kg/cm3
Block B density:0.020833 kg/cm3
Block C density:0.041667 kg/cm3
Answer:
a) Фm = μ₀*I*n*π*N*R₁²
b) Фm = μ₀*I*n*π*N*R₂²
Explanation:
Given
n = number of turns per unit length of the solenoid
R₁ = radius of the solenoid
I = current passing through the solenoid
R₂ = radius of the circular coil
N = number of total turns on the coil
a) Фm = ? If R₂ > R₁
b) Фm = ? If R₂ < R₁.
We can use the formula
Фm = N*B*S*Cos θ
where
N is the number of turns
B is the magnetic field
S is the area perpendicular to magnetic field B.
The magnetic field outside the solenoid can be approximated to zero. Therefore, the flux through the coil is the flux in the core of the solenoid.
We know that the magnetic field inside the solenoid is uniform. Thus, the flux through the circular coil is given by the same expression with R2 replacing R1 (from the area).
a) Then, the flux through the large circular loop outside the solenoid (R₂ > R₁) is obtained as follows:
Фm = N*B*S*Cos θ
where
B = μ₀*I*n
S = π*R₁²
θ = 0°
⇒ Фm = (N)*(μ₀*I*n)*(π*R₁²)*Cos 0°
⇒ Фm = μ₀*I*n*π*N*R₁²
b) The flux through the coil when R₂ < R₁ is
Фm = (N)*(μ₀*I*n)*(π*R₂²)*Cos 0°
⇒ Фm = μ₀*I*n*π*N*R₂²
Answer:
true
Explanation:
i've read about it in a bunch of different articles and stuff
Answer:
Explanation:
2.Big bang, 3.contraction of the solar nebula, 5.stellar ignition in our sun, 4.outgassing of earths secondary atmosphere, 1.appearance of the first ocean on earth ,7.evolution of photosynthesis, 6.build- up of oxygen in earths atmosphere.