Answer:
The kinetic energy of the heavier block after the push is equal to the kinetic energy of the lighter block
Explanation:
Kinetic energy of smaller object

where m= mass of smaller object and v= velocity of smaller object
Also, it is given that heavier object is four times the mass of lighter object and consider its velocity as V
kinetic energy of heavier block 
Now, For smaller block , 
[by Newtons laws of motion]
Also, 
Where S= displacement, F= force, u= initial velocity
So, ![K=(1/2)m[2(F/m)]S](https://tex.z-dn.net/?f=K%3D%281%2F2%29m%5B2%28F%2Fm%29%5DS)

For heavier block ,

or, 
So,

Therefore the kinetic energy of the heavier block after the push is equal to the kinetic energy of the lighter block
Can you reword the sentence?
Answer:
Time, t = 8 seconds
Explanation:
An object is thrown upward from the top of a 128-foot building with an initial velocity of 112 feet per second. The height h as a function of time t is given by :

We need to find the time when the object will hit the ground. When it will hit the ground, h = 0
So,

On solving the above quadratic equation, we get the value of t = 8 seconds. So, after 8 seconds the object will hit the ground. Hence, this is the required solution.