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Mumz [18]
3 years ago
11

A, B and E are non-collinear O True O False​

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

it would be false

Step-by-step explanation:

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write the standard equation of a circle that is tangent to the x-axis with the center located at (2,4)​
dmitriy555 [2]

Answer:

Step-by-step explanation:

radius=4 as it is tangent to x-axis.

y co-ordinate of center is 4 so radius=4

eq. of circle is (x-2)²+(y-4)²=4²

or x²-4x+4+y²-8y+16=16

or x²+y²-4x-8y+4=0

4 0
3 years ago
The capacity of a beamer is 0.1 liter. convert this to milliliters
Vladimir [108]

A milliliter is a thousandth of a liter. 1,000 milliliters (mL) are in a liter. So, multiply 0.1 by a thousand to find the answer. The answer is 100.

3 0
4 years ago
if one Circle has a diameter of 10 cm and a second Circle has a diameter of 20 cm what is the ratio of the area of the larger ci
Oxana [17]
Area of a circle is πr^2.

The radius of the smaller circle with diameter 10 cm is 5 cm.

The radius of the larger circle with diameter 20 cm.is 10 cm.

Area of larger circle : Area of smaller circle

Area of larger circle = 100π.

Area of smaller circle = 25π.

Ratio = 100π : 25π or 100π/25π.

7 0
3 years ago
1/3^-1-1^-1/4^-1<br>find the value in the following equation ​
nadezda [96]

Answer:

-1/6

Step-by-step explanation:

= 1/3 (-1-1) x -1/4 (-1)

= 1/3 (-2) x 1/4

= -2/3 x 1/4

= -2\12

2 and 12 can cancel out each other.

so the answer will be.

= -1/6.

4 0
3 years ago
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
levacccp [35]
f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3

f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5

f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}
4 0
3 years ago
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