2 years ago

HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP

1 answer:

4 0

$f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3$

$f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5$

$f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}$

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2 years ago

Read 2 more answers

3/8=a/2= 15/b<br>find a and b

Studentka2010 [4]

Answer:

Step-by-step explanation

$\frac{3}{8}=\frac{a}{2}\\\\\frac{3}{8}*2=a\\\\a=\frac{3}{4}\\\\\\\frac{3}{8}=\frac{15}{b}\\\\ 3*b=15*8\\\\b=\frac{15*8}{3}\\\\b=5*8\\\\b=40$