Answer: I am so sorry i hadn't learned this Yet~!
Explanation:
5 N to the right
There’s a force of 6 N pulling to the right (the positive direction) and 1 N pulling left (the negative direction).
Net force= 6 N - 1 N = 5 N to the right
An example is when u rub your pen on your hair hard that is friction
Answer:
v = 15 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

where:
P = linear momentum [kg*m/s]
m = mass = 2 [kg]
v = velocity = 15 [m/s]
![P=2*15\\P=30 [kg*m/s]](https://tex.z-dn.net/?f=P%3D2%2A15%5C%5CP%3D30%20%5Bkg%2Am%2Fs%5D)
Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.
![30=2*v\\v = 30/2\\v = 15 [m/s]](https://tex.z-dn.net/?f=30%3D2%2Av%5C%5Cv%20%3D%2030%2F2%5C%5Cv%20%3D%2015%20%5Bm%2Fs%5D)
Answer:
v₀ = 26.17 m/s
Explanation:
If
R = Xmax = 50 yards = (50 yards)*(0.9144 m / 1 yard) = 45.72 m
t = 5 s (Time of Flight)
we can apply the equation:
R = V₀x*t ⇒ V₀x = R / t = 45.72 m / 5 s ⇒ V₀x = 9.144 m/s
then we use the equation of Time of Flight:
t = 2*V₀y / g ⇒ V₀y = g*t / 2 = (9.81 m/s²)*(5 s) / 2 ⇒ V₀y = 24.525 m/s
Finally we apply
v₀ = √(V₀x² + V₀y²) ⇒ v₀ = √(9.144² + 24.525²) m/s
⇒ v₀ = 26.17 m/s