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Ira Lisetskai [31]

3 years ago

10

if two objects masses 8kg and 24 kg are dropped from top of a building. Which one reaches the ground first

2 answers:

Nadusha1986 [10]3 years ago

6 0

They will reach the grouns at the same time if we neglect.
Y=1/2 gt²
There is know mass needed in the equation

kherson [118]3 years ago

5 0

<h3>the object weighing 24 kg ( kilograms ) will reach the ground first</h3>

if two objects are the same size but one is heavier, the heavier one has greater density than the lighter object
so when both objects are dropped from the same height and at the same time, the heavier object should hit the ground before the lighter one

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Every complete circuit includes a device that provides emf. What type of quantity?

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Answer:

energy per unit charge

Explanation:

EMF is energy per unit charge and has unit joule/ coulomb, where joule is unit of energy and coulomb is the unit of charge.

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A certain spring has a spring constant k1 = 660 N/m as the spring is stretched from x = 0 to x1 = 35 cm. The spring constant the

pantera1 [17]

(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².

(b) The work done, in stretching the spring from x1 to x2 is 11.25 J.

(c) The work, necessary to stretch the spring from x = 0 to x3 is 64.28 J.

<h3>Work done in the spring</h3>

The work done in stretching the spring is calculated as follows;

W = ¹/₂kx²

W(1 to 2) = ¹/₂K₂Δx²

W(1 to 2) = ¹/₂(250)(0.65 - 0.35)²

W(1 to 2) = 11.25 J

W(0 to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃

W(0 to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)

W(0 to 3) = 64.28 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

6 0

2 years ago

An airplane, flying horizontally at an altitude of 3 miles, passes directly over an observer. If the constant speed of the air

natima [27]

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6 0

3 years ago

Once Kate's kite reaches a height of 50 ft (above her hands), it rises no higher but drifts due east in a wind blowing 7 ft d

Margaret [11]

Answer:

dz = 7.136 (answer)

Explanation:

given height for kate's kite = 50 ft (say y)

due to drift it move towards east = dx = 7 ft

string maximum length = 107 ft ( say z)

we have to find change in z

that is dz

it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse

so we get according to Pythagoras Theorem

$z^2 = x^2+y^2\\$ ...............(i)

by derivative both side consider y as constant

$2zdz = 2xdx\\dz = {xdx }/z$

from (i) equation

$x = \sqrt{z^2-y^2}$

$dz = \sqrt{z^2-y^2}dx/z$

now put the value and find dz

$dz = (\sqrt{120^2-50^2)}7/107\\ =((\sqrt{14400 -2500} )\times7)/107$

after solving these we get

$dz =\frac{109.08\times7}{107}$

dz = 7.136 (answer)

7 0

3 years ago