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LenaWriter [7]
2 years ago
9

Household chores are a good way to fit exercise into your everyday ruotine

Physics
1 answer:
MrMuchimi2 years ago
3 0
True, but is that your question?
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It takes you 8.3 min to walk with an average velocity of 1.6 m/s to the north from the bus stop to the museum entrance. How far
Anarel [89]

solution:

1.6 m/s = 96 m/min (in other words, 1.6 m/s x 60 s/min)  

96 m/min x 8.3 min = 796.8 m

s=ut +\frac{1}{2}at^2\\there is no accleration mentioned so,\\s= uv\\8.3\times60=498(s)\\510\times1.6=816(m)


3 0
3 years ago
What is the mass of a child in a wagon that has a velocity of 10 m/s and a Momentum of 30 KG* M/S
LenKa [72]

Explanation:

sinces : Momentum = velocity × mass

then : 30 = 10 × m and m = 30 ÷ 10 = 3 kg

3 0
2 years ago
The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star
Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

PV=nRT

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

V is the volume of a sphere

V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3

V=8.86*10^{50}L

and for n

n=\frac{(4000M_s)/(2*mH)}{6.022*10^{23}mol^{-1}}=3.95*10^{36}mol

Hence, we have (1 Pa = 9.85*10^{-9}atm)

T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K

hope this helps!!

8 0
2 years ago
In the diagram, the trough of the wave is shown by:
Kisachek [45]

Answer:

the correct representation of the trough is b

3 0
3 years ago
20 miles per hour north is an example of ______
timofeeve [1]
B. It's an example of velocity due to the fact that it has a measurement of speed, divided by time, and has a specific direction. Acceleration doesn't have any direction on it, but has speed divided by time. C and D have a different mode of measurement despite of the fact that it still needs meters/miles/km.
4 0
2 years ago
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