Answer:
Step-by-step explanation:
It maybe will be ![\neq x^{2} \leq \\ \\ \int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx \sqrt{x} \\ \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. x^{2} x^{2} \sqrt{x} \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \sqrt{x} \sqrt[n]{x} \frac{x}{y} \frac{x}{y} \alpha \beta x_{123} \\ x^{2} \int\limits^a_b {x} \, dx x^{2}](https://tex.z-dn.net/?f=%5Cneq%20x%5E%7B2%7D%20%5Cleq%20%5C%5C%20%5C%5C%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%5Csqrt%7Bx%7D%20%5C%5C%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20x%5E%7B2%7D%20x%5E%7B2%7D%20%5Csqrt%7Bx%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%5Cneq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Cfrac%7Bx%7D%7By%7D%20%5Calpha%20%5Cbeta%20x_%7B123%7D%20%5C%5C%20x%5E%7B2%7D%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20x%5E%7B2%7D)
1. Distribute the Negative Signs
2. Combine like terms
-2x^2 + 12x-7
Answer:
(1, 3)
Step-by-step explanation:
Given coordinates of 2 endpoints, G(-2, 5) and H(4, 1), midpoint of AB is calculated as shown below:
Midpoint (M) of GH, for G(-2, 5) and H(4, 1) is given as:

Let 

Thus:



Coordinates of the midpoint of GH = (1, 3).
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The value of x is 
Step-by-step explanation:
From the question we are told that
The length of the vertical length is 
The length of the base leg is L = 330 + d units
The length of the bisecting line segment is h
The base angle is 
The angle between d and line segment is 
For the first angle

=> 
For the whole big triangle

=> 
So equating the both d

Substitute values




Answer:
3500 - 10% = 3150 rupees
Step-by-step explanation:
the customer will pay 3150 rupees